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infinite recursion

Definição

1. endless repetition where output of one step is input for the next 2. endless loop in... Ver mais

Tradução de "infinite recursion" em chinês

Definição

NEW

无限递归

Make sure you do not have an infinite loop or infinite recursion.

确保您没有无限循环或无限递归。

Next, we need to deal with the problem of infinite recursion.

接下来，我们需要解决无限递归的问题.

So, this class does not actually do anything interesting: it just converts any instances of its own to regular ndarray (otherwise, we'd get infinite recursion!), and adds an info dictionary that tells which inputs and outputs it converted. Hence, e.g.,

所以，这个类实际上并没有做任何有趣的事情：它只是将它自己的任何实例转换为常规的ndarray（否则，我们将获得无限递归！），并添加一个info字典，告诉它转换了哪些输入和输出。因此，例如，

The form referred to itself during construction from a default instance, which led to infinite recursion. Within the Form's constructor refer to the form using 'Me.'

窗体在从默认实例构造期间引用自身，这导致了无限递归。在窗体的构造函数中使用"Me"引用窗体。

But did not last long, Six months, In another app, Quiver, I also encountered this problem, This is not so easy to solve, The same approach would lead to infinite recursion... Well, It's time to actually use the technologies.

不过好景不长，时隔半年，在另一个 app， Quiver 中又遇到了这个问题，这次就没那么容易解决了，同样的办法会导致无限递归……好吧，是时候使用真正的技术了。

Implementations of List.sort() must not call Collections.sort(), because doing so would result in stack overflow due to infinite recursion.

List.sort （）的实现不能调用 Collections.sort （），因为这会导致堆栈因无限递归而溢出。

Cannot use a target macro to resolve PrimaryOutput as this causes infinite recursion.

不能使用目标宏解析 PrimaryOutput，因为这将导致无限递归。

Doing so, the call is very likely to invoke one of the subclass's overridden init methods and it will result in infinite recursion.

如果这样，调用很可能会调用一个子类重写的 init 方法并且陷入无限递归之中。

If this option is enabled, the search will follow symlinks to directories. This can lead to infinite recursion if cyclical symlinks exist.

如果启用此选项，搜索会跟随指向目录的符号链接。但如果存在循环的符号链接，这可能导致搜索进程陷入死循环 。

Exceptions thrown from within the event handler will not be caught. Instead the process will exit with a non-zero exit code and the stack trace will be printed. This is to avoid infinite recursion.

此事件的监听器回调函数中抛出的异常，不会被捕获。为了避免出现无限循环的情况，进程会以非零的状态码结束，并打印堆栈信息。