Factoring out the lambda squared and bringing it over to the right, on the left hand side we get log of x minus one half log lambda minus x, minus one half log
Factoring a la lambda cuadrada y llevarla a la derecha, la izquierda lado tenemos registro de x menos lambda de registro una mitad menos x, menos de la mitad de registro
So it's going to be lambda is an eigenvalue for A, and we saw that lambda squared will be the eigenvalue for A squared and lambda inverse minus 1 will be the value inverse minus the identity, and the eigenvectors will be the same.
Así que va a ser lambda es un autovalor de a y vio lambda cuadrado será el valor propio de un cuadrado e inversa lambda menos 1 será el valor inversa menos la identidad y la vectores propios será el mismo.
lambda minus x times lambda plus x equal one over lambda squared two times one over x, plus one over two lambda2, squared times one over lambda minus x, minus one over two lambda2, squared times one over lambda plus x.
Lambda menos x veces lambda plus x igual un excedente lambda cuadrado dos veces uno sobre x, más uno sobre dos lambda2, cuadrado de épocas uno sobre lambda menos x, menos uno lambda2 sobre dos, cuadrado uno sobre lambda plus x veces.
We get lambda squared, right, minus 3 lambda, minus lambda, plus 3, minus 8, is equal to 0.
Obtenemos lambda cuadrada, correcto, menos 3 lambda, menos lambda, mas 3, menos 8, es igual a 0.
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Synonyms and analogies of "lambda squared" in English