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that a function
Vertaling van "that a function" in Chinees
声称一个函数
Too coarse a resolution means that a function with a sharp change might not be represented very well.
太粗略的分辨率意味着有急剧变化的函数可能不能很好表示。
Another common misconception is that a function can't cross its asymptote.
另外一个常见误解是， 一个函数不可能和它的渐近线相交.
We know that a function can access variables outside of it, this feature is used quite often.
我们知道函数可以访问其外部变量；这是一个常用的特性。
Isn't that a function of the home?
这不是家里的事吗？
Isn't that a function of the home?
这不是家里的事吗？
We say that a function is "lifted into the monad" by the lifting operators.
并不是说，函数的每次求值结果都相同。
In languages that allow side effects, like most object-oriented languages, subtyping is generally not sufficient to guarantee that a function can be safely used in the context of another.
允许副作用的语言，如大部分面向对象语言，子类型化还不足以保证安全在另一个上下文中使用。
More accurately, this is expressed by saying that a function preserves all existing suprema (or infima), and it may well be that the posets under consideration are not complete lattices.
更精确地说，这被表达为声称一个函数保持所有"现存"上确界（或下确界），所考虑的偏序集合不是完全格也可以如此。
One useful corollary is that a function is continuous if and only if its curried form is continuous.
而有用的推論是，一個函數若且唯若其柯里化形式是連續時，它才是連續的。
A conference on multi-channel-age audience and broadcasters on the influences that television broadcasting might have on minors and the consequent countermeasures to be taken reported that a function which automatically controls the audience on a temporary basis (parental-lock function) would be beneficial.
关于电视广播可能对未成年人产生的影响和因此应采取的对付措施的多信道时代观众和广播公司会议报告说，对观众的临时自动控制功能（"家长锁住功能"）会是有益的。
By default, you have to put quotes when you call a function. It is possible to use the unquoted keyword to indicate that a function does not require quotes for its arguments.
默认情况下， 调用一个函数需要引号. 可以使用 unquoted 关键字指明一个函数的参数不需要使用引号.
This characterization states that a function is primitive recursive if and only if there is a natural number m such that the function can be computed by a Turing machine that always halts within A(m, n) or fewer steps, where n is the sum of the arguments of the primitive recursive function.
这个特征声称一个函数是原始递归的，当且仅当有一个自然数 m 使得这个函数可以被总在 A（m ，n ） 或更少步骤内停机的图灵机计算，这里的 n 是原始递归函数的参数的总数。 限制 ［ 编辑 ］
Now there is a problem here, namely that a function which is not Riemann integrable may be represented as a uniformly bounded series of Riemann integrable functions.
现在有一个问题在这里，即函数并非黎曼可积可派代表作为一致有界一系列的黎曼可积的功能。
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