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type of the function

Vertaling van "type of the function" in Chinees

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函数的类型
The parameters that were specified for the functions are shown in brackets. By clicking with the left mouse button or using the "Enter" key one can go to the definition of the selected function in the file. Each type of the function has its own icon in the list
为函数指定的参数显示在括号中。通过点击鼠标左键或使用 "Enter"键可以进入文件中的所选函数的定义。 列表中,每个函数的类型都有其自己的图标:
Its data type is the actual return type of the function, as deduced from the actual input types (see Section 35.2.5).
它的数据类型将实际的返回函数的类型,从实际的输入类型返回(见Section 35.2.5 ) 。
The operand is not compatible with the type of the function.
操作数与函数类型不兼容。
type of the function is optional here, because the type can
在此处是可选的,因为类型可以从
The return type of the function can be specified after the arguments list using the arrow token (->)
可以在参数列表之后使用箭头标记(->)指定函数的返回类型:
This is also used on the return value, in this case to ensure that the result of adding 1 to i will be an integer (as otherwise it could become too large), and to mark the return type of the function.
这也用于返回值,在该情况下确保添加1到i的结果将是一个整数(否则可能变得太大),并标记函数的返回类型。
In a function call, if the operand of a return statement is a prvalue and the return type of the function is the same as the type of that prvalue.
object 是一个左值表达式,它的类型是T T 的基地,是同样或更小的品种合格的,然后引用绑定的左值或基类的子对象的对象标识的对象.
function. The return type of the function is inferred from
函数的返回类型根据
The <func-name> must be a valid MiniZinc identifier, and each <arg-def> is a valid MiniZinc type <ret-type> is the return type of the function which must be the type of <exp>. Arguments have the same restrictions as in predicate definitions.
<函数名> 必须是一个合法的MiniZinc标识符。每一个 <参数定义> 是一个合法的MiniZinc类型声明。 <返回类型> 是函数的返回类型,它必须是 <表达式> 的类型。参数和谓词定义中的参数有一样的限制。
A use of the function '{0}' does not match a type inferred elsewhere. The inferred type of the function is {1}. The type of the function required at this point of use is {2} {3}This error may be due to limitations associated with generic recursion within a 'let rec' collection or within a group of classes. Consider giving a full type signature for the targets of recursive calls including type annotations for both argument and return types.
对函数"{0}"的使用与在其他位置推理出的类型不匹配。推理出的函数的类型为 {1}。 此时需要使用的函数的类型为 {2} {3}此错误可能是由于与一个"let rec"集合或一组类中的泛型递归相关联的限制所导致的。请考虑为递归调用的目标给定完整的类型签名,包括参数和返回类型的类型批注。
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